1. From a point 20 m away from the foot of a tower, the angle of elevation of the top of the tower is 30°. The height of the tower is





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  • By: anil on 05 May 2019 01.53 am
    Perpendicular AB= height of tower Base BC = distance b/w base of tower and the point Hypotenuse AC= segment b/w top of the tower and the point Angle of elevation ACB =30° tan 30° = Perpendicular / Base = 1/√3 Perpendicular = Base*1/√3 Base is 20 m. So height of tower is 20/√3m.
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