1. If sin 21°= x/y then sec21°- sin 69° is equal to





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  • By: anil on 05 May 2019 01.53 am
    Given , sin 21°= x/y . So , cos21°=$$sqrt{1-sin^{2}21°}$$ . cos21=$$sqrt{1-(frac{x}{y})^{2}}$$
    So, sec21°= $$frac{1}{cos21^{circ}}$$
    Also sin69°=cos21°.
    Hence, sec21°-sin69° = $$frac{1}{sqrt{1-(frac{x}{y})^{2}}}$$ - $$sqrt{1-(frac{x}{y})^{2}}$$
    = $$frac{x^2}{ysqrt {y^2-x^2}}$$
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