1. The milk and water in two vessels A and B are in the ratio 4 : 3 and 2 : 3 respectively. In what ratio, the liquids in both the vessels be mixed to obtain a new mixture in vessel C containing half milk and half water ?
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- By: anil on 05 May 2019 01.53 amFraction of milk in vessel A = $$frac{4}{7}$$ Fraction of milk in vessel B = $$frac{2}{5}$$ Fraction of milk in vessel C = frac{1}{2}$$ Using, rule of alligation, required ratio = $$x : y$$ $$ x : y $$ = $$frac{4}{7} : frac{2}{5}$$ Mean fraction : $$frac{1}{2}$$ => $$(frac{1}{2}-frac{2}{5}) : (frac{4}{7}-frac{1}{2})$$ [Using Alligations] => $$frac{1}{10} : frac{1}{14}$$ => $$x : y$$ = $$frac{1}{10} : frac{1}{14} = 7 : 5$$
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