1. The difference between the compound interest and the simple interest for a period of 2 years at the rateĀ of 10% per annum is Rs. 50. Find the principal.
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By: anil on 05 May 2019 01.38 am
Let the principal amount = $$Rs. 100x$$
Time = 2 years and rate = 10% => $$C.I. = P [(1 + frac{R}{100})^T - 1]$$ = $$100x [(1 + frac{10}{100})^2 - 1]$$ = $$100x [(frac{11}{10})^2 - 1] = 100x (frac{121 - 100}{100})$$ = $$100x imes frac{21}{100} = 21x$$ => $$S.I. = frac{P imes R imes T}{100}$$ = $$frac{100x imes 10 imes 2}{100} = 20x$$ It is given that difference between compound and simple interest = $$21x - 20x = 50$$ => $$x = 50$$ $$ herefore$$ Principal = $$100 imes 50 = Rs. 5,000$$
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Time = 2 years and rate = 10% => $$C.I. = P [(1 + frac{R}{100})^T - 1]$$ = $$100x [(1 + frac{10}{100})^2 - 1]$$ = $$100x [(frac{11}{10})^2 - 1] = 100x (frac{121 - 100}{100})$$ = $$100x imes frac{21}{100} = 21x$$ => $$S.I. = frac{P imes R imes T}{100}$$ = $$frac{100x imes 10 imes 2}{100} = 20x$$ It is given that difference between compound and simple interest = $$21x - 20x = 50$$ => $$x = 50$$ $$ herefore$$ Principal = $$100 imes 50 = Rs. 5,000$$