1. In a bag there are 4 white, 4 red and 2 green balls. Two balls are drawn at random. What is the probability that at least one ball is of green colour ?
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By: anil on 05 May 2019 01.30 am
There are 4 white, 4 red and 2 green balls and two balls are drawn at random. Total possible outcomes = Selection of 2 balls out of 10 balls = $$C^{10}_2 = frac{10 * 9}{1 * 2} = 45$$ Favourable outcomes = 1 green ball and 1 ball of other colour + 2 green balls = $$C^2_1 imes C^8_1 + C^2_2$$ = 2*8 + 2 = 18 $$ herefore$$ Required probability = $$frac{18}{45} = frac{2}{5}$$
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