1. A,B C D and E are five consecutive odd numbers. Average of A and C is 59. What is the smallest number ?
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By: anil on 05 May 2019 01.26 am
Let the five numbers be a, a+2, a+4, a+6 and a+8. The average of A and C is 59.
Therefore, a + a+4 = 2*59
Or 2a + 4 = 118
Therefore, a = 57 Hence, the smallest number is 57.
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Therefore, a + a+4 = 2*59
Or 2a + 4 = 118
Therefore, a = 57 Hence, the smallest number is 57.